Arrow is just the dot version while accessing elements of a struct/class that is a pointer instead of a reference.

struct foo
{
  int x;
  float y;
};

struct foo var;
struct foo* pvar;
pvar = malloc(sizeof(struct foo));

var.x = 5;
(&var)->y = 14.3;
pvar->y = 22.4;
(*pvar).x = 6;

Why parenthesis are in use?

. is standard member access operator that has a higher precedence than * pointer operator.

To make the compiler know that dereference acts on the struct, but not on the element, the parethesis have to be added properly.

Based on discussion.